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3 years ago

Which graph represents the solution set of y = x2 + 4x + 3 and y = 2x + 6?

Mathematics

2 answers:

Len [333]3 years ago

7 0

Here ya go!! Hope this helps, come to me if you need any more help

alisha [4.7K]3 years ago

4 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have that

$y=x^{2} +4x+3$ ------> equation A

$y=2x+6$ ------> equation B

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

see the attached figure

The solutions are the points $(-3,0)$ and $(1,8)$

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Write an algebraic expression for the following: twice a number *

Sliva [168]

2x ! the number would be x and 2x is 2 times x!

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3 years ago

Read 2 more answers

In most linear programming problems, there are two stages:

xxMikexx [17]

Answer: Bruno = 16 cans, Blaze = 14 cans

Step-by-step explanation:

Part A gave you the three equations.

Part B showed you the intersected points --> (16, 14), (20, 10), & (21.4, 10.7)

Part C is giving you the Cost function: C(x, y) =0.10x + 0.20y

Input the intersected points into the Cost function to find the maximum.

C(16,14) = 0.10(16) + 0.20(14)

= 1.60 + 2.80

= 4.40

C(20,10) = 0.10(20) + 0.20(10)

= 2.0 + 2.00

= 4.00

C(21.4,10.7) = 0.10(21.4) + 0.20(10.7)

= 2.14 + 2.14

= 4.28

Of the three results we just found, 4.40 is the biggest value.

So, the maximum occurs at C(16,14) = 4.40

↓ ↓

Bruno Blaze

5 0

3 years ago

-7x-4=13 how do u show the work and how do u check it

ioda

Answer:

Step-by-step explanation:add 4 to the side that has "13" then you will get "17" then divided -7 from x and "17"and your answer is x=idk

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4 years ago

A total of $6000 was invested, part of it at 3% interest and the remainder at 8%. If the total yearly interest amounted to $380,

Nastasia [14]

$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest

Solution:

Given that, total of $6000 was invested

Let "x" be the amount invested at 3 % interest

Then, (6000 - x) is the amount invested at 8 % interest

Given that,

The total yearly interest amounted to $380

Then, we can frame a equation as:

$x \times 3 \% + (6000 - x) \times 8 \% = 380$

Solve the above expression for "x"

$x \times \frac{3}{100} + (6000-x) \times \frac{8}{100} = 380\\\\0.03x + (6000-x) \times 0.08 = 380\\\\0.03x + 480 - 0.08x = 380\\\\-0.05x = -100\\\\\text{Divide both sides by -0.05 }\\\\x = 2000$

Thus, $ 2000 is invested at 3 % interest

(6000 - x) = 6000 - 2000 = 4000

$ 4000 is invested at 8 % interest

4 0

4 years ago

The sum of four consecutive whole numbers is 230.Find the numbers.

taurus [48]

х is the first number
(x + 1) is the second number
(x + 2) is the third number
(x + 3) is the fourth number

x + x+1 + x+2 + x+3 = 230
4x + 6 = 230
4x = 230 - 6
4x = 224
x = 224/4
x = 56 the first number
56 + 1 = 57 the second number
56 + 2 = 58 the third number
56 + 3 = 59 the fourth number

Answer: 56, 57, 58, 59.

7 0

3 years ago