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vodka [1.7K]
2 years ago
14

Write an algebraic expression for the following: twice a number *

Mathematics
2 answers:
Sliva [168]2 years ago
4 0
2x ! the number would be x and 2x is 2 times x!
lianna [129]2 years ago
3 0

Answer:

2x

Step-by-step explanation:

1. when a number and a variable are right beside eachother it means that you would multiply them. the equation 2x is the same as 2•x but is simplified to 2x

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7 0
3 years ago
In standard notation 208.06 is written as
andreyandreev [35.5K]

Answer:

2.0806 × 10²

Step-by-step explanation:

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I really need help on this i dont know how to do it.
Juli2301 [7.4K]

Answer:

Step-by-step explanation:

25x = 300

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3 years ago
Which of the following is a complex number?<br> -7<br> 2 + StartRoot 3 EndRoot<br> 4 + 9i<br> Pi
zepelin [54]
Second to last one is my guess
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Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
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