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goldenfox [79]
3 years ago
11

What is one source for the variation that drives natural selection?

Chemistry
2 answers:
Inessa05 [86]3 years ago
8 0
Over production because it
otez555 [7]3 years ago
6 0
The answer is over production
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Give one example of Lewis acid
erma4kov [3.2K]

Answer:

<em><u>Copper </u></em><em><u>(</u></em><em><u>Cu2)</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>Iron </u></em><em><u>(</u></em><em><u>Fe2+</u></em><em><u> </u></em><em><u>Fe3 </u></em><em><u>+</u></em><em><u>)</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>and </u></em><em><u>Hydrogen </u></em><em><u>ion </u></em><em><u>(</u></em><em><u>H+</u></em><em><u>)</u></em>

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What 2 solutions could help restore the ecosystem back to normal?
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2 years ago
A solution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.15 ∘c. what is the molal concentration of glucose in this solution
Reil [10]
<span>1.16 moles/liter The equation for freezing point depression in an ideal solution is ΔTF = KF * b * i where ΔTF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case ΔTF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get ΔTF = KF * b * i ΔTF/KF = b * i ΔTF/(KF*i) = b And substuting known values. ΔTF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
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3 years ago
What state of matter is at 35 Celsius
Otrada [13]
Different forms of matter have different melting/boiling points. For example, at 100 degrees Celsius, H2O (water) will turn from lliquid to gas. But NaOH (table salt) doesn't even go from solid to liquid until some 800 degrees Celsius. So, in order to figure out which state matter is at 35 Celsius, you'd have to be more specific about what kind of matter...
7 0
3 years ago
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