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sasho [114]
3 years ago
15

What is the Kb expression for aniline (C6H5NH2)?

Chemistry
2 answers:
Dimas [21]3 years ago
4 0
This is what i got The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ <span>OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]

hope this helps:)

</span>
navik [9.2K]3 years ago
3 0

the answer is A for #platofam

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Dry ice goes directly from the solid phase to the gas phase. What phase
Marianna [84]

Answer:

Sublimation is being represented.

Sublimation is the transition from solid to gas state

Hope this helps! Have a good day!

8 0
3 years ago
Read 2 more answers
Lastly, Snape thinks we should try one more calculation. What is the retention factor if the distance traveled by the solvent fr
Neporo4naja [7]

Answer:

0.1 is the retention factor.

Explanation:

Distance covered by solvent ,d_s= 2.0 cm

Distance covered by solute or ion,d = 0.20 cm

Retention factor(R_f) is defined as ratio of distance traveled by solute to the distance traveled by solvent.

R_f=\frac{d}{d_s}

R_f=\frac{0.20 cm}{2.0 cm}=0.1

0.1 is the retention factor.

7 0
3 years ago
Copper chloride bihydrate. What might this name tell you about the atoms in this compound
lozanna [386]

Answer : The atoms in this compound are Copper(Cu), Chlorine(Cl), Hydrogen(H), Oxygen(O).

Explanation :

The given compound is copper chloride bi-hydrate which is also called as copper (II) chloride dihydrate as it contains two water of crystallisation.

The formula of copper chloride bi-hydrate is CuCl_2.2H_2O.

Therefore, there are 4 atoms in this compound and they are Copper(Cu), Chlorine(Cl), Hydrogen(H) and Oxygen(O).

6 0
3 years ago
Consider the following reaction at equilibrium. 2CO2 (g) 2CO (g) + O2 (g) H° = -514 kJ Le Châtelier's principle predicts that th
tiny-mole [99]

Answer:

C. at low temperature and low pressure.

Explanation:

  • <em>Le Châtelier's principle </em><em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

<em />

  • For the reaction:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g), ΔH = -514 kJ.</em>

<em></em>

<em><u>Effect of pressure:</u></em>

  • When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
  • The reactants side (left) has 2.0 moles of gases and the products side (right) has 3.0 moles of gases.

<em>So, decreasing the pressure will shift the reaction to the side with higher no. of moles of gas (right side, products), </em><em>so the equilibrium partial pressure of CO (g) can be maximized at low pressure.</em>

<em></em>

<u><em>Effect of temperature:</em></u>

  • The reaction is exothermic because the sign of ΔH is (negative).
  • So, we can write the reaction as:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g) + heat.</em>

  • Decreasing the temperature will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the temperature, <em>so the equilibrium partial pressure of CO (g) can be maximized at low temperature.</em>

<em></em>

  • So, the right choice is:

<em>C. at low temperature and low pressure.</em>

<em></em>

7 0
3 years ago
What would be the empirical formula of a compound that is 25.5% carbon, 6.40% hydrogen, and 68.1% oxygen?
aleksandr82 [10.1K]
Empirical formula is the simplest ratio of whole numbers of components in a compound 
in 100 g of compound 
                                C                          H                          O
mass                   25.5 g                     6.40 g                 68.1 g
number of moles  25.5 g/12 g/mol      6.40 g/ 1 g/mol      68.1 g/ 16 g/mol 
                             = 2.13 mol              = 6.40 mol          = 4.26 mol
divide by least number of moles 
                             2.13/2.13 = 1          6.40/2.13 = 3.0    4.26/2.13 = 2.0
all rounded off 
C - 1
H - 3
O - 2

empirical formula - CH₃O₂
8 0
3 years ago
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