How do you do this question?
1 answer:
Answer:
(B) only I and II
Step-by-step explanation:
An odd relation is symmetrical about the origin. All of the relations are odd.
An even relation is symmetrical about the y-axis. Only the first two relations are even.
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The graph shows the first relation is that of a circle. It is symmetrical about its center at the origin and about any diameter, including the y-axis.
The second relation is a degenerate hyperbola. It graphs as the pair of lines y=x and y=-x. It is symmetrical about both the origin and the y-axis. (It also has other lines of symmetry.)
The third relation is a line with slope -1 (represented by dots). It is symmetrical about the origin, but not the y-axis. It is only an odd relation.
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Answer:
Step-by-step explanation:
We are given the following in the question:
A(1, 1), B(2, 4), C(4, 2)
i) Slope of AB
Thus, slope of AB is 3.
ii) Point slope form
The point slope form of a line can be written as:
The point intercept form of line can be written as:
The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB
Putting values, we get,
which is the required slope intercept equation of line p.