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denpristay [2]
2 years ago
12

Find the slope of the line y=1/6x+3/2

Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

Answer:  slope = 1/6

Reason:

The given equation is in slope-intercept form y = mx+b

m = 1/6 = slope

b = 3/2 = y intercept

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What is the product?<br> (-282 +8)(502-65)
Tju [1.3M]

Answer:

option c is the answer for pic

and for question the answer is

(-274)*(437)

-119738

7 0
3 years ago
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L.F. Richardson proposed a model to describe the spread of war fever. His proposal: If y(t) is the percent of the population adv
Lena [83]

Answer:

y'(t)=ky(t)(100-y(t))

Step-by-step explanation:

The rate of change of y(t) at any time is the derivative of y with respect to time y, y'(t)

If y(t) is the percent of the population advocating war at time t

then 100-y(t)  is the percent of the population not advocating war

The product of the percentage of the population advocating war and the percentage not advocating war would be

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If the rate of change of y(t) at any time is proportional to the product of the percentage of the population advocating war and the percentage not advocating war, then

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3 years ago
6x-1=11 solve equation
marin [14]

Answer:

x = 2

Step-by-step explanation:

6x-1=11

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6x-1+1=11+1

6x = 12

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5 0
3 years ago
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PARK is a parallelogram. Find the value of x.
jekas [21]

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Step-by-step explanation:

8 0
3 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

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95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
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