Since V = (4/3) * pi * R^3
If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8
So V' = (1/8)V
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer: slope = 1/2
Step-by-step explanation:
X-2y=10
-2y=-x-10 subtract x from both sides
2y=x+10 divide by -1
y=<u>1</u> x + 5 Divide by 2
2
slope = 1/2
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
24.4 mL
By converting mm to cm, we get
1 mm = 1/10 cm
18 mm = 18/10 cm
radius (r) = 1.8 cm
To find the volume,
Volume of sphere = 4/3πr3
= 4/3π(1.8)3
Volume = 24.4 cm3
To find the capacity,
1 cm3 = 1 mL
Capacity = 24.4 mL
