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xxTIMURxx [149]
3 years ago
10

Please helpppp it’s due at 5 part 1

Mathematics
1 answer:
Anna [14]3 years ago
3 0

Answer:

I think the first one is B

Step-by-step explanation:

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For the geometric sequence: 112.5, 225, 450, 900,..., find the 21st term.
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Step-by-step explanation:

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3 years ago
PLS HELP!! A student randomly guesses the answers to two true-false questions. Describe and correct the error in finding the pro
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Answer:

The student was wrong. The probability is actually 1/4.

Step-by-step explanation:

Let's say you have question A and question B. You could have incorrect on A, and incorrect on B. Or, you could have incorrect on A, but a correct on B. Or, you could have an incorrect on B, but a correct on A. Or, both could be correct. <em><u>Since there are 4 different possibilities, the actual probability is 1/4.</u></em>

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3 years ago
Find k such that the equation kx^2+x+25k=0 has a repeated solution.
Paha777 [63]
Ill try to answer your question
4 0
4 years ago
A rectangular prism has volume 4,800 cubic yards, length 20 yards, and height 40 yards. Find its width, in yards.​
Oksi-84 [34.3K]

Answer: 6 yards.

Step-by-step explanation:

First, multiply the length and the height to get 800. You know now that 800 times the width will be your volume, 4800. To find the width, divide the volume by 800, which is the length times the height. Check your work by doing 40 times 20 times 6. You get 4800, which is your volume, which means your correct!

8 0
3 years ago
what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
Dmitrij [34]
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
3 0
3 years ago
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