What are the solutions to -x^2+100x

Pls answer as soon as possible what is 5.3 rounded?

Nadusha1986 [10]

Answer:

5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Choose the correct measure of an astronomical unit. 9.3 million miles .93 million miles 93 million miles 930 million miles

Genrish500 [490]

By definition, an astronomical unit in miles is given by:
$1 AU = 9.3 * 10 ^ 7 miles
$
As it is in exponential notation, then we must rewrite.
$9.3 * 10 ^ 7 = 93,000,000 miles
$
Therefore, an astronomical unit is:
93 million miles
Answer:
93 million miles

8 0

3 years ago

The volume of a cylinder can is 1.54 litre and area of base is 77cm^2 Find its height

goblinko [34]

Answer:

The height is 20 cm.

Step-by-step explanation:

First, we have to know that the volume formula is V = πr²h and the base area of cylinder is a circle. So we can let πr² be 77 cm² . Then we have to substitute the following values into the formula :

$v = 1.54 \: l$

$v = 1540 \: {cm}^{3}$

$v = \pi \times {r}^{2} \times h$

Let πr² be 77,

Let v be 1540,

$1540 = 77 \times h$

$77h = 1540$

$h = 1540 \div 77$

$h = 20 \: cm$

5 0

3 years ago

Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropria

TiliK225 [7]

GIVEN

The following values are given:

$\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}$

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

$z=\frac{x-\mu}{\sigma}$

For x = 9:

$\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}$

For x = 14:

$\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}$

The probability can be calculated as follows:

$P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671$

The probability is 0.4671.

8 0

1 year ago

The abdominopelvic region that is bordered by all four imaginary lines is the

Ainat [17]

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

4 0

3 years ago