∫ e^(3x)*(cosh(2x)dx
= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx
= ∫ [(e^(5x)+e^x)/2]dx
=e^(5x)/10+e^x/2+C
=(1/10)(e^(5x)+5e^x)+C
Answer:
For x, the equation is 
Step-by-step explanation:
Given: the equation x over 3-5=y
We have to solve for x,
Consider the given equation the equation x over 3-5=y
Here, over means divide, so,
Mathematically written as ,

Solving foor x,
adding 5 both sides, we have,

On solving, we have,

Now, multiply both side by 3, we have,

On simplification, we have,

Thus, for x, the equation is 
Sum of {(-5i + 2) from i = 1 to 10} =
= - 5{ (Sum i) from 1 to 10} + (sum of 2) from 1 to 10
= - 5 {1 + 10)*10/2} + 2{10} =
= -5(11)(5) + 20 = -275 + 20 = - 255
In vertex form the equation of the parabola is
y = a(x + 4)^2 - 1 where a is the coefficient of the squared term.
When x = 2 y = 0 so:-
0 = a(2 + 4)^2 - 1
0 = 36a - 1
a = 1/36 <----- Answer