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kodGreya [7K]
3 years ago
6

Coffee cost 5$ per pound how much dose 7 pounds cost

Mathematics
2 answers:
LuckyWell [14K]3 years ago
4 0
7 pounds of coffee cost 35$
tangare [24]3 years ago
4 0
It would cost $35. At $5 dollars a lb, 7 lbs would cost 35 dollars
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5/8 of 10 liters please :)​
Finger [1]

Answer:

6.25liters

Step-by-step explanation:

5/8 × 10

Lcm is 8

5×10/8

50/8

6.25

So 5/8 of 10liters is

6.25liters

4 0
2 years ago
Read 2 more answers
What is the product of 2x + y and 5x – y + 3? x2 + xy + x + y2 + y
miskamm [114]

Answer: 10x^2+3xy+6x-y^2+3y

Step-by-step explanation:

You need to remember the Product of powers property:

(a^m)(a^n)=a^{(m+n)}

Then, knowing this property, now you have to apply the Distributive property. So:

(2x+y)(5x-y+3)=\\\\=(2x)(5x)-(2x)(y)+(2x)(3)+(y)(5x)-(y)(y)+(y)(3)\\\\=10x^2-2xy+6x+5xy-y^2+3y

Finally, to simplify this expression, you need to add the like terms.

Therefore, you get that the product is:

=10x^2+3xy+6x-y^2+3y

3 0
3 years ago
Read 2 more answers
What is 21/4 in simplest form
scZoUnD [109]
This is already in simplest form. it can't be reduced furthermore.

As a mixed number is 5 1/4

As a decimal is 5.25
3 0
2 years ago
I need help!!!!!! AGAIN!!!!!Find the perimeter of the trapezoid. (round to the nearest hundredth)
inysia [295]
(12 x 9) + (12 x 6/2). The answer would be 144 but rounded it would be 100
4 0
3 years ago
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Need help finding the x, y, and z. please and thank you
Reptile [31]

The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

... 2x +z = -4 . . . . simplified

Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)

...15x +3y -12z +2x -3y +z = 123 -1

...17x -11z = 122 . . . . simplified

Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

... 11(2x +z) +(17x -11z) = 11(-4) +122

...22x +17x = 78 . . . . . . simplify a little bit

... x = 78/39 = 2 . . . . . . divide by 39

From above, we find

... z = -4 -2x = -4 -2·2 = -8

... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1

The solution is (x, y, z) = (2, -1, -8).

_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

4 0
2 years ago
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