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lozanna [386]
3 years ago
13

For the relation given, do the following:

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

1.No

2.No

3.Transitive

Step-by-step explanation:

We are given that a relation

R_3={(0,0),(0,1),(0,2),(1,2)}

If a relation is reflexive then (a,a) belongs to relation for each a belongs to given set.

A relation is symmetric

If (a,b)\in R then, (b,a)\in R

A relation is transitive

(a,b) and (b,c)\in R then, (a,c)\in R

1.The relation is not reflexive because (1,1) does not  belongs to R_3

2.The relation is not symmetric because (2,0)in R_3

3.It is transitive because (0,1) and (1,2)\in R_3 then (0,2)[tex\in R_3[/tex]

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Answer:

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Step-by-step explanation:

5 ( x-2)^2 +6 = 86

Subtract 6 from each side

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Divide each side by 5

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3 years ago
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anzhelika [568]

Answer:

<h2><u>b = 2 or b = -2</u></h2>

Explanation:

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<em>Solve absolute value</em>

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Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)

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2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>

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3 years ago
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Factor 5 de 5t - 5
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