What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?

1 answer:

5 0

First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165

This will be used in the formula below

Sn = n*(a1+an)/2
Sn = n*(151+(-14n+165))/2
S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
S26 = -624

The final answer here is choice C) -624

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\\\text{Dividing both sides by 1.96,}
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\\\frac{0.04}{1.96}=\sqrt{\frac{0.63(0.37)}{n}}
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\\\text{Squaring both sides,}
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