3 years ago

Rozwiąż równania:

1 answer:

3 0

$a)\\x-7=(7-x)-(14-2x)\\x-7=7x-14+2x\\x-7=-7+x\\b)\\x-4x+(2x+3)=6(3-x)\\x-4x+2x+3=18-6x\\-x+3=18-6x\\-x+6x=18-3\\5x=15 //:5\\x=3\\c)\\2x+15=16(1+0,125x)\\2x+15=16+2x\\15=16$

You might be interested in

Pls can someone help me<br><img src="https://tex.z-dn.net/?f=%20log10%20%5Csqrt%7B36%7D%20%20%2B%20%20%20%20log10%20%20%5Csqrt%7

Firlakuza [10]

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$