Answer:
1600 integers
Step-by-step explanation:
Since we have a four digit number, there are four digit placements.
For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.
For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.
For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers
Answer:
You take turns plugging in each number for your answers. I’ll list them below.
6(0) - (0)2 = 0
6(1) - (1)2 = 4
6(2) - (2)2 = 8
6(3) - (3)2 = 12
6(4) - (4)2 = 16
6(5) - (5)2 = 20
6(6) - (6)2 = 24
The pattern I’ve noticed is every time you increase the value from the previous meaning for x, the solution increases by 4. I hope this helps and let me know if I’m right.
Answer:for number one its q and r and then its w,x,y for the second one
Step-by-step explanation:
hope its helps
You have to give more explanation
