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denis-greek [22]
3 years ago
10

Please help........................

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

a. (0,0), (2,0), (4,0)

b. (0,0)

Step-by-step explanation:

To find the x-intercept points, you set the equation equal to 0.

0=x³-6x²+8x                                [factor out an x]

0=x(x²-6x+8)                                [factor (x²-6x+8)]

0=x(x-2)(x-4)                               [set each factor equal to 0]

<u>x=0</u>

x-2=0                                           [add both sides by 2]

<u>x=2</u>

x-4=0                                            [add both sides by 4]

<u>x=4</u>

Now, we know our x-intercept points: (0,0), (2,0), (4,0).

To find the y-intercept points, we know that it is located on the y-axis, meaning x=0. We plug in 0 for x, and we will know our y-intercept point.

y=(0)³-6(0)²+8(0)                         [multiply]

y=0

The y-intercept point is (0,0).

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