Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).
34.76
o
, nearly.
Explanation:
Angle of elevation = arc tan( (vertical height)/(length os the shadow)).
Here, this angle is
arc tan (12.5
/
18) =
34.78
o
, nearly
Answer:
Follows are the solution to this question:
Step-by-step explanation:
- It is true because the square of the standard error of its estimate was its total square error divided only by the degree of freedom.
- It is true because Its coefficient with Standardized Regression, beta, will have the same value as r, the approximate similarity.
- It is false because Its slope b, of its equation of regression, will have the same value as r, the projected correlation.
3a+11=7a-13
move 7a to the other side
sign changes from +7a to -7a
3a-7a+11= 7a-7a-13( combine like terms)
3a-7a+11= -13
-4a+11= -13
move 11 to the other side
sign changes from +11 to -11
-4a+11-11= -13-11
-4a= -13-11
-4a= -24
divide both sides by -4 to get a by itself
-4a/-4= -24/-4
Answer: a= 6
