3 years ago

Please help 20 points

Mathematics

2 answers:

loris [4]3 years ago

4 0

Answer:

10 4/7

Step-by-step i used photo math

Gala2k [10]3 years ago

3 0

Answer:

Step-by-step explanation:

But where’s the question

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For each mile Jason runs Megan runes 1/4 mile farther if Jason ran 6 miles how far did Magen run ?

fenix001 [56]

Let, Jason = J and M = Megan

M = J(1 + 1/4)

So putting 6 where J is and solving:
M = 6(1 + 1/4)
M= 7.5

When Jason runs 6 miles Megan runs 7.5

4 0

2 years ago

Read 2 more answers

Find all critical values of the function g(x)=5/(x²-x+6)

Sati [7]

$g(x)=\frac{5}{x^2-x+6}\\\\D:x^2-x+6\neq0\\\\\Delta=(-1)^2-4\cdot1\cdot6=1-24=-23 < 0\\\\x\in\mathbb{R}\\\\vertex\ of\ y=x^2-x+6\\\\p=\frac{-(-1)}{2\cdot1}=\frac{1}{2}\\\\q=\frac{-(-23)}{4\cdot1}=\frac{23}{4}\\\\\lim\limits_{x\to\frac{1}{2}}\frac{5}{x^2-x+6}=\frac{5}{\frac{23}{4}}=\frac{5\cdot4}{23}=\frac{20}{23}$

$\lim\limits_{x\to\pm\infty}\frac{5}{x^2-x+6}=0$