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3 years ago

Please help 20 points

Mathematics

2 answers:

loris [4]3 years ago

4 0

Answer:

10 4/7

Step-by-step i used photo math

Gala2k [10]3 years ago

3 0

Answer:

Step-by-step explanation:

But where’s the question

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tank contains 250 liters of fluid in which 20 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5

eimsori [14]

Solution :

Given data :

$c_{in}$ = 1 g/L

$r_{in}$ = 5 L/min

$r_{out}$ = 5 L/min

$v_0$ = 250 L

$A_0$ = 20 g

∴ $r_{net} = r_{in}- r_{out}$

= 5 - 5

= 0

$c_{out} = \frac{A}{250} \ g/L$

Now, $\frac{dA}{dt}=(r_{in} \times c_{in}) - (r_{out} \times c_{out})$

$\frac{dA}{dt} = 5-5\left(\frac{A}{250}\right)$

$\frac{dA}{dt}+5 \left(\frac{A}{250}\right) = 5$

$\frac{dA}{dt}+5 \left(\frac{A}{250}\right) = 5 \text{ with} \ A_0 = 20$

Integrating factor = exp(5 t/250)

Therefore,

$A \times \exp (5t \ /250) = \text{integral of}\ 5 \times \exp (5t / 250) + C$

Put $A_0=250+C$

C = -230

$A \times \exp(5t/250) = 250 \exp(5t/250) + (-230)$

$A(t) = 250-230 \exp(-5t/250)$

$A(t) = 250-230e^{\left(\frac{-t}{50}\right)} \ g$

5 0

3 years ago

Can someone help with this please?

NemiM [27]

I’m pretty sure it’s C.

3 0

3 years ago

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r-ruslan [8.4K]

3,680,010 is the answer

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3 years ago

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(3a x3 -5bx3) + -------ax3 + -----------bx3 = (ax3 + bx3).

Sonja [21]

3a x3 ax ax3 (ax47) 12 5 ca

4 0

4 years ago

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a ramp 29 ft long rises to a platform. the bottom of the platform is 20 ft from the foot of the ramp. find x, the angle of eleva

Simora [160]

We will be using the cosine function to figure this out.
The ramp, ground, and platform form a right triangle.
The hypotenuse is 29, and the side adjacent to ∠x is 20.
SO:
Cos ∠x = 20/29
Cos ∠x = 0.68965517241379

Use the function on your calculator to find what angle has a Cos of 0.6896551
Cos 0.6896551 = 46.397°

ANSWER: the angle of elevation is 46.4°

Hope this helps! God bless. :)

3 0

3 years ago