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3 years ago

HELPPP

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

Answer:

Step-by-step explanation:

JUST SOLVE IT THEN YOU GOT THE ANSWERIVE SOLVED THIS DONTWORRY

<h2>#CARRYONLEARNING!</h2>

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-58 3 - 3 1 - 0<br> Solve.

jarptica [38.1K]

Answer:

$-9\frac{1}{4}$

Step-by-step explanation:

Rewrite our equation with parts separated

-5 - $\frac{3}{4}$ - 3 - $\frac{1}{2}$

Solve the whole number parts

-5 - 3 = -8

Solving the fraction parts and Find the LCD

LCD = 4

$-\frac{3}{4}$ - $\frac{2}{4}$ = $-\frac{5}{4}$

Simplify

$-\frac{5}{4} = -1\frac{1}{4}$

Combine the whole and fraction parts

8 - 1 - $\frac{1}{4}$ = $-9\frac{1}{4}$

Mark as Brainllest

5 0

3 years ago

Simplify 4 square root of 2 end root plus 7 square root of 2 end root minus 3 square root of 2

ehidna [41]

Answer:

8√2

Step-by-step explanation:

4√2 + 7√2 - 3√2 = (√2)(4 + 7 - 3) = 8√2

Recognize that √2 is a common factor and simply add its coefficients.

6 0

3 years ago

Read 2 more answers

Guys please help me with this problem<br><br> Make a list of the possible outcomes from the table

Elena-2011 [213]

Answer:

(d)

Step-by-step explanation:

The answer is d because it's pretty simple , you can have the white shirt with both trousers and the green shirt with both aswell.

7 0

3 years ago

Question Solve: x - 18 = –103. Provide your answer belo

Alexxandr [17]

Answer:

x=-85

Step-by-step explanation:

x-18=-103

x=-103+18

x=-85

6 0

3 years ago

Read 2 more answers

URGENT: statistics: A researcher wishes to estimate the percentage of adults who support abolishing the penny what size sample s

irina1246 [14]

Using the margin of error for the z-distribution, the sample sizes are given as follows:

a) 822.

b) 1068.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

We have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

Item a:

The estimate is of $\pi = 0.26$ , hence we solve for n when M = 0.03.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.26(0.74)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.26(0.74)}$

$\sqrt{n} = \frac{1.96\sqrt{0.26(0.74)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.26(0.74)}}{0.03}\right)^2$

n = 821.2

A sample of 822 is needed.

Item b:

No prior estimate, hence $\pi = 0.5$ .

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.03}\right)^2$

n = 1067.11

A sample of 1068 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0

2 years ago