Answer:
None is wrinkled and waxy
Explanation:
Spliting the alleles and pairing them usng the two characters listed, The male pea plant will have four possible alleles: RS, Rs, rS, and rs. The female also we have the same. Using punnet's square, we are to cross the two parents, Using gentotypes obtained from this cross; RRSS, RRSs, RrSS, RrSs, RRSs, RRss, RrSs, Rrss, RrSS, RrSc, rrSS, rrSs, RrSs, Rrss, rrSs, rrss. The phenotupic ration will be 9 Round starchy: 3 Round waxy: 3 Wrinkled starchy: 1 wrinkled waxy. It cannot be said that none of the progeny will be wrinkled waxy.
" What does passive transport mean " Good sentence or no
Answer:
0%
Explanation:
From the information given;
Assume that the dominant "B" allele encodes brown eyes ; and
the recessive "b" allele encodes blue eyes
If genotype BB × genotype bb, the percentage of chance that they would have children with blue eyes will be zero ...Let look at the cross
BB × bb
We have all the progeny as Bb, Bb, Bb, Bb ....i.e the genotypic information are all heterozygous brown eyes, this is because The allele B mask the recessive "b" allele which makes the allele B (brown eyes) to be dominant over allele b (blue eyes).
Answer:
The Food has to digest
Explanation:
Your Stomach doesn't realize you've overeaten until your body starts to break it down.
