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tiny-mole [99]
3 years ago
14

How many variable terms are in the expression 3x3y + 5x2 − 4y + z + 9?

Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0
Maybe 16 im not sure if not 16 there is 5
crimeas [40]3 years ago
5 0
Three. twenty characters 
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If A is an n× n matrix, then det A = det AT . Verify this theorem for 2 × 2 matrices.
Bond [772]

Answer:

Verified

Step-by-step explanation:

Let A matrix be in the form of

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Then det(A) = ad - bc

Matrix A transposed would be in the form of:

\left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Where we can also calculate its determinant:

det(AT) = ad - bc = det(A)

So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices

4 0
3 years ago
And, what is the least common multiple of 6,15, and 5
iren2701 [21]

Answer:

there is no multiplyer becuase 1 dosnt work no 2 nor3 nor4 nor5 nor6 and then you will be greater than 6 so it dosnt fit into 5 so

????/

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
CAN SOMEONE ANSWER JUST S4 PLEASE
Sergio039 [100]

Answer:

9x -18+18=43+18

Step-by-step explanation:

added 18 to both sides

hope this helps good luck :)

3 0
4 years ago
How do u solve 50=pi*2(h+3)
lakkis [162]

\bf 50=\pi 2(h+3)\implies 50=\stackrel{\textit{distributing first}}{2\pi h+6\pi }\implies 50-6\pi =2\pi h \\\\\\ \cfrac{50-6\pi }{2\pi }=h\implies 4.957747154594767 \approx h

5 0
3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
4 years ago
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