Answer: the incubation time that separates the bottom 2.5% from the rest of the incubation times is 24.96 days.
Step-by-step explanation:
Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times.
µ = mean time
σ = standard deviation
From the information given,
µ = 23 days
σ = 1 day
The probability value for the incubation time that separates the bottom 2.5% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975
Looking at the normal distribution table, the z score corresponding to the probability value is 1.96
Therefore,
1.96 = (x - 23)/1
x = 1.96 + 23
x = 24.96
Answer:
4
Step-by-step explanation:
terrible, but it could be worse
783-366=417
Difference = Subtraction
2 and 5? 25/12? Don't get what you mean
