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3 years ago

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Equation of a line that passes through (2,-3) with the slope of 1/2

2 answers:

Irina18 [472]3 years ago

7 0

In point slope form:
y+3=1/2(x-2)

In slope intercept
y= 1/2x-4

Mashcka [7]3 years ago

7 0

The equation fo a line that passe sthrout the point (x1,y1) and having a slope of m is
y-y1=m(x-x1)
given

point i (2,-3) and slope is 1/2
y-(-3)=1/2(x-2)
y+3=1/2(x-2)
y+3=1/2x-1
y=1/2x+2

y=1/2x+2 or y+3=1/2(x-2) or x-2y=-2

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QUESTION 3 of 10: Stock returns vary from year to year. The more variance a stock displays the greater the potential risk. These

Dahasolnce [82]

Answer:

The variance of these investment returns is 74

Step-by-step explanation:

Given:

Series = 10, 30, 15, 5, 20

To Find:

variance of a series = ?

Solution:

The variance of the series = $Var\left(X\right)=\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n}$

$\bar{x} = \frac{10+30 +5+15 + 20}{5}$

$\bar{x} = \frac{80}{5}$

$\bar{x} =16$

Now $(x_i -\bar{x})^2 =$ $(10 -16)^2 + (30 -16)^2 + (5 -16)^2 +(15 -16)^2 +(20 -16)^2$

= $(-6)^2 + (14)^2 + (-11)^2 + (-1)^2+ (-4)^2$

= 36 + 196 +121 + 1+ 16

= 370

Now

$Var\left(X\right)=\frac{370}{5}$ = 74

6 0

3 years ago

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A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

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3 years ago

1. The word sum

MariettaO [177]

Answer:

Multiplication

Step-by-step explanation:

I believe 2x2 would have a sum of 4.

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Please answer for brainliest

Finger [1]

2^3/2

= √2^3

= √8

answer

A. first option

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Solve for 20-u=3u simplify answer

Aleonysh [2.5K]

<h3>Step-by-step explanation: Solve for <em>u</em> by simplifying both sides of the equation, then isolating the variable . u=5</h3>

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