We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
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I hope my answer has come to your help. God bless and have a nice day ahead!
(arrange the data set from least to greatest)
0, 0, 2, 2, 3, 4, 6, 8
(find the median: *the middle number*)
Median: 2.5
Lower quartile: 1
Upper quartile: 5
Interquartile range : upper quartile - lower quartile = answer
Interquartile range: 5 - 1 = 4
So the IQR or interquartile for the following data set is 4.
Answer:
Subtract the two diameters and multiply by 0.5
Step-by-step explanation:
Calculating the Radius of the hole gives distance to the inner edges WHILE the Radius of the coin gives us the distance to the outer edges.
By subtracting the output we can then get the difference between both distances.
If hole diameter = 5mm and coin diameter = 22mm
Difference = [(22 - 5)mm] ÷ 2
17mm / 2 = 8.5mm
Answer:
<h2>a = 11</h2>
Step-by-step explanation:
Y=mx+b
lines are parallels so m=2
y=2x+b
line passing through the point (4,2), so x=4 y=2
put these value in equation
2=2*4+b
2=8+b
b=2-8
b=-6
y=2x-6
Answer: y=2x-6
(verification on the picture)