Answer: it will be 45, but for some reason it’s not in your answer choices
Step-by-step explanation:
There’s no photo attached or anything
So firstly, the three terms share a GCF of x, so factor that out: 
Next, I'm going to be factoring by grouping. But first, what two terms have a product of 140x^2 and a sum of 33x? That would be 28x and 5x. Replace 33x with 5x + 28x: 
Now factor 20x^2 + 5x and 28x + 7 separately, make sure that they have the same quantity on the inside: ![x[5x(4x+1)+7(4x+1)]](https://tex.z-dn.net/?f=%20x%5B5x%284x%2B1%29%2B7%284x%2B1%29%5D%20)
<u>Now you can rewrite the expression as
, which is your final answer.</u>
C
The numbers and symbols move 1 place in the next square. The symbols change from shaded to non shaded and the numbers of the first 2 squares add up to the one in the 3rd.