F(3)=4(3)+3(exchange all “x” for 3
f(3)=12+3(multiply 4 times 3)
f(3)=15(add 3 to 12)
Answer:
Step-by-step explanation:
V = x(14 - 2x)(18 - 2x)
V = (14x - 2x²)(18 - 2x)
V = (252x - 28x² - 36x² + 4x³)
V = 4x³ - 64x² + 252x
V' = 12x² - 128x + 252
0 = 3x² - 32x + 63
x = (32 ±√(32² - 4(3)(63))) / (2(3)
x = (32 ± √268) / 6
x = 8.06 inches, which we ignore as this would mean we have no material left at all in the 14 inch dimension.
or
x = 2.60488... 2.60 inches
Vmax = 0.60(14 - 2(2.60))(18 - 2(2.60)) = 292.86478... = 292.86 inches³
The number of bars which can be cut for the 1" X 1" and 2" X 2" square bars are; 117 and 29 units respectively.
<h3>How many bars can be cut from the pan in each case?</h3>
The total area of the given pan can be evaluated as follows;
Area = length × width
= 9 × 13
= 117 square units.
Hence, the number of 1" X 1" bars can be cut which can be cut from the pan;
= 117/(1×1)
= 117 1" X 1" bars.
For the 2" X 2" square bars, we have;
= 117/(2×2);
29 remainder 1 square unit.
Ultimately, one square unit of the pan is wasted for the 2" X 2" square bars.
Read more on area;
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Answer:
SUre, 2, 3 5
Step-by-step explanation:
