The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
s = (1/2)√(a²+b²)
You do 5 times x and -2 so you’d get 5x-10=7. Then add 10 to both sides to get 5x=17 and divide 17/5 to get 3.4
38 rounds to 40.
29 rounds to 30.
40 x 30 = 120.
Answer:
Step-by-step explanation:
<u>21. 1st scenario</u>
- B = fy + wz
- 100,000 = 15,000*4 + 500w
- 500w = 100,000 - 60,000
- 500w = 40,000
- w = 40,000/500
- w = 80
80 tons of wheat
<u>22. 2nd scenario</u>
- B = fy + wz
- 50,000 = 2y + 200*50
- 50,000 = 2y + 10,000
- 2y = 50,000 - 10,000
- 2y = 40,000
- y = 20,000
Fighter plane's price is $20,000
The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have:
f(x) = 1/√x
m(x) = x² - 4
Domain of f(x)/m(x):
f(x)/m(x) = (1/√x)/(x² - 4)
f(x)/m(x) = 1/√x(x² - 4)
The denominator cannot be zero:
√x(x² - 4) ≠ 0
x(x - 2)(x+2) ≠ 0
x ≠ 0, 2, -2
and x > 0
Domain of f(x)/m(x) is: (0, ∞) - {0, 2, -2} or 
Domain of f(m(x)):
f(m(x)) = 1/√(x² - 4)
x² - 4 > 0
Domain: 
Domain of m(f(x)):
= ((1/√x)² - 4)
Domain: 
Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
Learn more about the function here:
brainly.com/question/5245372
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