Answer:
Carl has 35 dimes and 90 quarters
Step-by-step explanation:
Let the number of quarters be q and the number of dimes be d
Total number of coins is 125;
Hence;
q + d = 125 •••••••••(i)
The total value of quarters present = q * 0.25 = 0.25q
The total value of dimes present = d * 0.1 = 0.1d
Adding both gives the total
0.25q + 0.1d =26 ••••••••(ii)
So we need to solve both equations simultaneously;
From i,
q = 125 - d
Substitute this into ii
0.25(125-d) + 0.1d = 26
31.25 -0.25d + 0.1d = 26
31.25 -26 = 0.25d -0.1d
5.25 = 0.15d
d = 5.25/0.15
d = 35
Recall; q = 125 - d = 125 -35 = 90
Answer:
i believe it is (2,1)
Step-by-step explanation:
Answer:
5.25 tablespoons are needed per dozen
Step-by-step explanation:
Solve for x in 2nd equation
times -1 both sides
x-5=6y
add 5
x=6y+5
sub
5(6y+5)+4y=-26
30y+25+4y=-26
34y+25=-26
minus 25 both sides
34y=-51
divide both sides by 34
y=-3/2
sub back
x=6y+5
x=6(-3/2)+5
x=-18/2+5
x=-9+5
x=-4
(-4,-3/2) is solution
i have no idea about a but
B. LN corresponds to EF
MN corresponds to DF
E corresponds to L
F corresponds to N
