Given :
The half-life of carbon 14 is 5,730 years.
To Find :
How much would be left of an original 50-
gram sample after 2, 292 years.
Solution :
We know, rate law for first order reaction is given by :
...1)
Here, is initial amount and is final amount.
And
Putting value of half time in above equation, we get :
Putting value of k in equation 1) , we get :
Hence, this is the required solution.
Answer:
y = mnp/(m + n)
Step-by-step explanation:
I assume that both capital y and small case y are meant to be the same variable. If not, let me know, and I'll solve it again for small case y.
y/m + y/n = p
Factor y out on the left side.
y(1/m + 1/n) = p
y = p/(1/m + 1/n)
Multiply the right side by (mn)/(mn).
y = pmn/[(1/m + 1/n)mn]
y = pmn/(n + m)
y = mnp/(m + n)
Answer:
I believe its D
Step-by-step explanation:
So to fine slope you would use the formula down below:
rise/run
So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.
So from 0,-5 go up 9 vertically, and you would be on the 4
Go horizontal 3 spots and your on a designated point.
So the rise is four and the run is 3
So 4/3 is the slope
In the y= Mx + b equation you would set the equation like this:
y= 4/3 + -5
The m in this formula stands for the slop and the b stands for the y-intercept
The y-intercept is the point that is on the y-axis and where it starts.