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kvv77 [185]
3 years ago
14

Help!!!!!!!!!!!!!!!!!!!!! No. 58

Mathematics
1 answer:
ELEN [110]3 years ago
8 0
Multiply then divide by 2
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No, because negative base sometimes results in non-real or imaginary value.

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The GCF of 28x^3 and 16x^2y^2
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If sin (x-3)° = cos (2x + 6)°, then what is the value of x?
Travka [436]

Answer:

if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.

----------

Note: sin and cos are complementary functions....

sin(x) = cos (90-x)

-------------------

Your Problem:

sin(x-3) = cos(90-(x-3))

Equation:

90-[x-3] = 2x+6

90-x+3 = 2x+6

3x = 93-6

x = 31-2

x = 29

Step-by-step explanation:

6 0
3 years ago
Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)
LenaWriter [7]

Answer:

The slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the points

  • (-1, -2)
  • (3, 4)

Determining the slope between (-1, -2) and (3, 4)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)

m=\frac{4-\left(-2\right)}{3-\left(-1\right)}

m=\frac{3}{2}

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

4=\frac{3}{2}\left(3\right)+b

switch sides

\frac{3}{2}\left(3\right)+b=4

\frac{9}{2}+b=4

subtract 9/2 from both sides

\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}

b=-\frac{1}{2}

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)

y=\:\frac{3}{2}x\:-\frac{1}{2}

Therefore, the slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}
8 0
3 years ago
Please help! will give brainliest!
sergeinik [125]
Answer:

Arc PL = 62
Arc QPS = 258

Explanation:

17. 5x-19 = 2x+11

18.

16x - 28 = 180.
7 0
2 years ago
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