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prohojiy [21]
3 years ago
13

Select the correct answer.

Computers and Technology
2 answers:
Nataly [62]3 years ago
7 0
Format is your answer. B.
miv72 [106K]3 years ago
3 0

Answer: Format

Explanation: My head

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Formulas should follow the___
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Order of operations

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the normal reasons program creators deliver to enroll your program – to get tech bolster, news, upgrades, offers, bug fixes, and so on. It too ensures your venture since it gives you changeless get to to your enlisted serial number in case something ever happens to your computer or computer program.

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Write an if statement to test if a number stored in y is between 6 and 10 inclusive.
lana66690 [7]

y = choose whatever number you want.

if 5 < y < 11:

   print("The value stored in y is between 6 and 10 inclusive")

else:

   print("The value stored in y is not between 6 and 10 inclusive.")

I hope this helps!

8 0
2 years ago
Using the flowchart diagram, identify the decision point of this solution. Identify vendors. Calculate amount due. Determine dat
andreev551 [17]

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answer is "is there an early pay discount"

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3 0
3 years ago
Read 2 more answers
Make a Backwards Phonebook from a Regular Phonebook
Dima020 [189]

Answer:

Code in Python is given. Take note of the instruction in bold font

Explanation:

You will need to update the below two lines in your system based on the file path -

backward_phone_number('F:\\phone_number_input.txt','F:\\phone_number_output.txt')

def backward_phone_number(input_file,output_file):

   ph_num_dictionary={}

   entries=[]

   #########################################################

   with open(input_file,'r') as read_file:

       entries=read_file.readlines()[1:]

   for entry in entries:

       ph_num_name=entry.split()

       ph_number=ph_num_name[1].strip()

       name=ph_num_name[0].strip()

       if ph_num_dictionary.get(ph_number)==None:

           name_list=[name]

           ph_num_dictionary[ph_number]=name_list

       else:

           ph_num_dictionary.get(ph_number).append(name)

   #########################################################

   ph_num_dictionary = dict(sorted(ph_num_dictionary.items(),key=lambda pair:pair[0]))

   with open(output_file,'w+') as write_file:

       write_file.write('Telephone Number\tName\r\n')

       for num,name in ph_num_dictionary.items():

           if len(name)==1:

               write_file.write(num+'\t'+name[0]+'\r\n')

           else:

               name.sort()

               for person in name:

                   write_file.write(num + '\t' + person + '\r\n')

backward_phone_number('F:\\phone_number_input.txt','F:\\phone_number_output.txt')

7 0
3 years ago
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