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MA_775_DIABLO [31]
3 years ago
13

Solve 5x - 10 <_ 20 pls help

Mathematics
1 answer:
balandron [24]3 years ago
6 0

Answer:

(-∞, 6]

Step-by-step explanation:

Step 1: Write inequality

5x - 10 ≤ 20

Step 2: Solve for <em>x</em>

  1. <u>Add 10 to both sides:</u> 5x ≤ 30
  2. <u>Divide both sides by 5:</u> x ≤ 6

Here we see that any value less than or equal to 6 would work.

∴ the 3rd option is our answer.

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Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]

X' = U - X

= {1,2,3,4,5,6} - {1,4,5}

= {2,3,6}

(ZUX') = {2,3,5} U {2,3,6}

= {2,3,5,6}

(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}

= {2}

3 0
3 years ago
A group of friends wants to go to the amusement park. They have $116 to spend on parking and admission. Parking is $10.25, and t
Alexus [3.1K]

Answer:

2 people

Step-by-step explanation:

no. of people = x

total parking costs = 10.25x

total tickets cost = 35.25x

total = 10.25x + 35.25x

suppose 3 people go, then the total cost will be

10.25(3) + 35.25(3) = 136.5 and this is greater than 116

Suppose 2 people go then the cost will be

10.25(2) + 35.25(2) = 91 which is less than 116

so only 2 people can go.

7 0
1 year ago
a force of 50 pounds stretches a spring 4 inches. how much force is required to stretch the spring 10 inches?
-BARSIC- [3]

Answer:

125 pounds

50/4 = 12.5 pounds stretches a spring to 1 inch

12.5x10=125 pounds of force

3 0
1 year ago
Help is appreciated! <br> What is the slope of the line, and what is the y-intercept?
Lady_Fox [76]
The slope is 1
The y-int is (0,-7)
3 0
2 years ago
Read 2 more answers
In a race in which eleven automobiles are entered and there are no ties, in how many ways can the first three finishers come in?
viva [34]

Answer:

990 ways

Step-by-step explanation:

The total number of automobiles we have is 11.

Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)

For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)

For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)

Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways

8 0
3 years ago
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