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3 years ago

SHOW YOUR WORK AS MUCH AS POSSIBLE 60 POINTS

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

The expression for the account is

a) 3600 -400M where m is the number of months

b) We want the expression to equal 2000

3600 -400M = 2000

c) 3600 is the initial amount in the account

400 is the amount that the account goes down each month

M is the number of months

2000 is the amount left in the account

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If u={1,2,3,4,5},A={2,4} and Beta {2,5,5}find n(AUB)

slavikrds [6]

u={1,2,3,4,5},A={2,4} and Beta {2,5,5}

now, (AUB)={1,3,3,4,5}

[AUB is the set of all elements of set A and set B without any repetition ]

n(AUB)=5

n(AUB)is the total no of elements in set (AUB)

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3 years ago

11-13 answers plssssss

labwork [276]

For 11, Figure B has the greatest perimeter. For 12, Figure C has an area of 108 square centimeters. For 13, Figure A has an area of 40 square feet.

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3 years ago

Read 2 more answers

HELP ASAP!right answer I’ll give you a crown

faltersainse [42]

Answer:

$y=-\frac{3}{2}x+1$

Step-by-step explanation:

Slope-intercept form means

$y=mx+c$

where m is given its the slope which is $-\frac{3}{2}$ and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,

$y=mx+c$

$-5 = -\frac{3}{2}(4)+c$

$-5=-6+c$

$c=1$

now we know the value of slope which is given $-\frac{3}{2}$ and we found the value of which is 1 so we put these values into our original slope-intercept form equation

$y=mx+c\\\\y=-\frac{3}{2}x+1$

4 0

3 years ago

Given that 1 kilogram weighs approximately 22 pounds, rewrite 10 pounds as an equivalent number of kilograms

yaroslaw [1]

Answer:

0.4545 kgs.

Step-by-step explanation:

Given that 1 kg weighs approximately 22 pounds.

i.e. 1kg= 22 lbs.

We can use this to convert lbs into kg.

22 lbs = 1 kg

Hence 1 lb = 1/22 = 0.04545 kg

Now to find out the equivalent weight for 10lbs,

we have conversion factor as 1 lb= 0.04545 kg

Hence 10 lbs = 10(0.04545) = 0.4545 kgs

Hence 10 pounds written in equivalent kgs would be0.4545 kgs.

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3 years ago

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so

alexgriva [62]

Solution :

Let $p_1$ and $p_2$ represents the proportions of the seeds which germinate among the seeds planted in the soil containing $3\%$ and $5\%$ mushroom compost by weight respectively.

To test the null hypothesis $H_0: p_1=p_2$ against the alternate hypothesis $H_1:p_1 \neq p_2$ .

Let $\hat p_1, \hat p_2$ denotes the respective sample proportions and the $n_1, n_2$ represents the sample size respectively.

$$\hat p_1 = \frac{74}{155} = 0.477419$

$n_1=155$

$$p_2=\frac{86}{155}=0.554839$

$n_2=155$

The test statistic can be written as :

$$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}$

which under $H_0$ follows the standard normal distribution.

We reject $H_0$ at $0.05$ level of significance, if the P-value or if $|z_{obs}|>Z_{0.025}$

Now, the value of the test statistics = -1.368928

The critical value = $\pm 1.959964$

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

$=2 \times 0.085667$

= 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$ , so we fail to reject $H_0$ at $0.05$ level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the $\text{proportion}$ of the seeds that $\text{germinate differs}$ with the percent of the $\text{mushroom compost}$ in the soil.

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3 years ago