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Ratling [72]
3 years ago
12

Help me please with this

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0
They're all $15.99 each
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What is the equation of the following graph in vertex form?
Veronika [31]

Answer:

The equation in vertex form is:

y=(x-2)^2+1

Step-by-step explanation:

Recall that the formula of a parabola with vertex at (x_{vertex},y_{vertex}) is given by the equation in vertex form:

y=a\,(x-x_{vertex})^2+y_{vertex}

where the parameter "a" can be specified by an extra information on any other point apart from the vertex, that parabola goes through.

In our case, since the vertex must be the point (2, 1), the vertex form of the parabola becomes:

y=a\,(x-x_{vertex})^2+y_{vertex}\\y=a\,(x-2)^2+1

we have the information on the extra point (0, 5) where the parabola crosses the y-axis. Then, we use it to find the missing parameter a:

y=a\,(x-2)^2+1\\5=a(0-2)^2+1\\5=a\,*\,4+1\\5-1=4\,a\\4=4\,a\\a=1

The, the final form of the parabola's equation in vertex form is:

y=(x-2)^2+1

5 0
3 years ago
If you reflect (-2,-8) across both axes, which quadrant<br> will it be in? Justify your reasoning.
Zepler [3.9K]
Search Results
Featured snippet from the web
Quadrant I
Answers. Sample Response: If (−2, −8) is reflected across both axes, it will be located at (2, 8), which is in Quadrant I. When a point is reflected across both axes, the signs of both the x- and y-coordinates change.
3 0
3 years ago
Read 2 more answers
Pls follow the steps and show work
WINSTONCH [101]
1st box: 2a (subtract 2a from both sides)
2nd box: 3 (add 3 to both sides)
3rd box: 10 (add 7+3)
4th and 5th box: 2 (divide both by 2)
6th box: 5 (10/2=5)


8 0
3 years ago
What is the next term of the geometric sequence? 2, -10, 50,
Anon25 [30]
To find the common ratio, divide the second term by the first term

-10 / 2 = -5

to find each term in a geometric sequence, u multiply by the common ratio.....
2 * -5 = -10
-10 * -5 = 50
50 * -5 = - 250 <== ur next term
3 0
3 years ago
Calculate a and b if
const2013 [10]

Notice that

7^{2014} - 7^{2012} = 7^{2012} \bigg(7^2 - 1\bigg) = 7^{2012} \times 48 = 2^4 \times 3 \times 7^{2012}

12=2^2\times3, so

\dfrac{7^{2014}-7^{2012}}{12} = 2^2 \times 7^{2012}

Then taking the positive square root gives

\sqrt{\dfrac{7^{2014}-7^{2012}}{12}} = \sqrt{2^2 \times 7^{2012}} = 2\times7^{1006}

so \boxed{a=2} and \boxed{b=1006}.

4 0
2 years ago
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