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Step2247 [10]
3 years ago
8

The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this

fluorocarbon, whereas under the same conditions, the 1-L volume holds only 1.70 g gaseous fluorine (F2). Determine the molecular formula of this compound.
Chemistry
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

molecular formula of CF₂ = 4 (CF₂) = C₄F₈

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Ilia_Sergeevich [38]
Answer: maybe 1.4 degrees higher than initial?

Not sure if all the needed info is here, I’m a bit rusty but I just tried to plug it into my calculator and got stuck. Anyway, the equation needed is Q=mcT, Q being energy, m mass, c spec. heat capacity and T as the change in temperature
8 0
3 years ago
A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

101.3 (\frac{0.0002}{296} )= 152 (\frac{V_{2} }{336} )

V_{2} = 0.000151 m^{3}

This is the final volume of the sample of gas.

4 0
4 years ago
How did they get the limiting reactant as O2???
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Better picture? you ksksmskakakaoa
5 0
3 years ago
How many moles are contained in 70. milliliters of a 0.167 M solution of p-toluidine hydrochloride? Enter only the number to two
kramer

<u>Answer:</u> The amount of p-toluidine hydrochloride contained is 2.4 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of p-toluidine hydrochloride solution = 0.167 M

Volume of solution = 70. mL

Putting values in equation 1, we get:

0.167=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{(0.167\times 70}{1000}=2.38mol=2.4mol

Hence, the amount of p-toluidine hydrochloride contained is 2.4 moles.

6 0
4 years ago
A neutral atom of Cl-37 has
Ostrovityanka [42]

Answer:

17 protons, 20 neutrons, and 17 electrons​.

Explanation:

A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.

Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

The mass number of this neutral atom of Cl-37 is 37 and we know that the atomic number (number of protons) of chlorine is 17. Also, the atomic number of an element is equal to the number of its electrons.

A neutral atom of Cl-37 has 17 protons, 20 neutrons, and 17 electrons.

Hence, a neutral atom of Cl-37 can be identified based on its number of protons because it represent its atomic number, which is what is used to differentiate an atom of an element from the atom of another chemical element.

6 0
3 years ago
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