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worty [1.4K]
3 years ago
15

How do I draw the a Lewis Structure for Iodine?Just need answer please :)

Chemistry
2 answers:
Elina [12.6K]3 years ago
8 0

Search ggl because we cannot add picture here.

Julli [10]3 years ago
7 0
Do u mean a lewis dot diagram? or a double bond of iodine (i2)??
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In complete sentences, Discuss two ways that earth is different from all the planets in our solar system.
TEA [102]

Answer:

it has plants and it has the best gravity

Explanation:

the reason why is because plants only exist on earth and and we have the best gravity because if we jump we don't jump to high like in other planets.

8 0
4 years ago
Determine whether the statement about identifying a halide is true: Regardless of any concentration of ammonium solution, the pr
frosja888 [35]

Answer:

False

Explanation:

The statement ; Regardless of any concentration of ammonium solution the precipitate of unknown halide after 0.1M AgNO3 will remain is FALSE

This is Because the remaining concentration of AgNO3 is dependent on the solubility of Ag⁺

3 0
3 years ago
Convert from 1.56×1030 particles of sodium chloride (NaCl) to grams of sodium chloride.
Anika [276]

Answer:

15.14×10⁷ g

Explanation:

Given data:

Number of particles of NaCl = 1.56×10³⁰ particles

Mass of sodium chloride = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ particles

1.56×10³⁰ particles × 1 mol / 6.022 × 10²³ particles

0.259 ×10⁷ mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.259 ×10⁷ mol × 58.44 g/mol

Mass = 15.14×10⁷ g

8 0
3 years ago
3. If 45.0 mL of 0.560 M KOH are needed to neutralize 125 mL of HCl of unknown concentration, what is
vlada-n [284]

Answer:

Molarity = 0.202 M

7.36 g/L HCl

Explanation:

KOH                        +                  HCl ----> KCl  +  H2O

1 mol                                           1 mol

0.560mol/L *0.045L                 x mol/L*0.125L

0.560mol/L *0.045L    =   x mol/L*0.125L

x = 0.560mol/L *0.045L  /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl

M(HCl) = 1.0+35.5 = 36.5 g/mol

0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl

6 0
4 years ago
What's the correct IUPAC name of the structure shown?
dimaraw [331]

Answer:

B.  4-methylhex-1-ene

Explanation:

There are 6 carbons for the main molecule of 1-hexene.  They are counted from the first (1) on the terminal C with the double bond (ene).  A methyl group is hanging on carbon number 4, so it is the 4-methyl.

4-methylhex-1-ene.

5 0
3 years ago
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