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jekas [21]
3 years ago
5

How many moles are contained in 70. milliliters of a 0.167 M solution of p-toluidine hydrochloride? Enter only the number to two

significant figures.
Chemistry
1 answer:
kramer3 years ago
6 0

<u>Answer:</u> The amount of p-toluidine hydrochloride contained is 2.4 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of p-toluidine hydrochloride solution = 0.167 M

Volume of solution = 70. mL

Putting values in equation 1, we get:

0.167=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{(0.167\times 70}{1000}=2.38mol=2.4mol

Hence, the amount of p-toluidine hydrochloride contained is 2.4 moles.

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3 0
3 years ago
How many moles are in 2.0 grams of Na?
lisov135 [29]

Answer:

46

Explanation:

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3 0
3 years ago
Please Help Me!
S_A_V [24]

Answer:

The answer to your question is      SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

Explanation:

Reaction

                                SO₂   +   H₂    ⇒     H₂S   +  H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                    1

                               2                  Hydrogen               4

                              2                   Oxygen                   1

This reaction is unbalanced so we need to balance it.

                              SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                   1

                              6                  Hydrogen               6

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3 0
3 years ago
How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?
nika2105 [10]

Answer:

m_{C_8H_{18}}=85.67gC_8H_{18}

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}}   \\\\m_{C_8H_{18}}=85.67gC_8H_{18}

Regards!

6 0
3 years ago
Calculate the percent by mass of 4.35g of Na I dissolved in 105g of water​
Ludmilka [50]

<u>We are given:</u>

Mass of Na added = 4.35 grams

Mass of water = 105 grams

<u>Mass Percent of Na:</u>

Total mass of the solution = mass of solute + mass of solvent

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Mass percent of solute = (mass of solute / mass of solution) * 100

Mass percent of Solute = (4.35 / 109.35) * 100

Mass percent = 3.978 %

4 0
2 years ago
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