<u>Answer:</u> The amount of p-toluidine hydrochloride contained is 2.4 moles.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of p-toluidine hydrochloride solution = 0.167 M
Volume of solution = 70. mL
Putting values in equation 1, we get:
Hence, the amount of p-toluidine hydrochloride contained is 2.4 moles.
Answer : The mathematical equation used when solving calorimetry problems is:
Explanation :
Calorimetry : It is determining the changes in the energy of a system by measuring the heat transferred with surroundings.
Formula used :
where,
c = specific heat capacity of calorimeter
m = mass of a substance
q = heat required
= change in temperature of substance
Answer:
Explanation:
This is a skeleton problem because the reacting species are not given. We do not have any information about the metal and non-metal reacting. Let us give a run down on how to solve this kind of problem. I hope you find it useful.
Firstly, establish the reaction equation. This will contain the reactants and products. The equation must be balanced in order to comply with the law of conservation of matter.
Secondly, solve from the known to the unknown specie. The known is the one which we can accurately determine the number of moles from. Using the number of moles of the known, we can find the moles of the unknown.
To find the number of moles;
Number of moles =
molar mass is the sum of the atomic masses of the given compound whose mass we know.
mass = 5g
Thirdly; compared the number of moles of the known to the unknown using relationships and ratios between the two of them. F
For example, if :
2 mole of known gives 1 moles of unknown
solved mole of the known will give moles of unknown
Lastly:
Now use this mole to find the mass of the unknown;
Mass of unknown = number of moles of unknown x molar mass
Answer:
93,32 % (w/w)
Explanation:
The Ca²⁺ of CaCO₃ was completely precipitate to CaC₂O₄ that results in H₂C₂O₄. The titration of this one is:
3H₂C₂O₄ + 2H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O + 6CO₂
As you required 35,62mL of 0,1092M MnO₄⁻, the moles of H₂C₂O₄ are:
0,03562L× =
3,890x10⁻³mol of MnO₄⁻× = <em>0,01167 mol of H₂C₂O₄</em>
The number of moles of CaCO₃ are the same number of moles of H₂C₂O₄ because every Ca²⁺ was converted in CaC₂O₄ that was converted in H₂C₂O₄. That means: <em>0,01167 mol of CaCO₃</em>
0,01167 mol of CaCO₃ are:
0,01167 mol of CaCO₃× = <em>1,168 g of CaCO₃</em>
As the mass of the initial mixture is 1,2516 g, the percentage by weight of CaCO₃ is:
×100 = <em>93,32 % (w/w)</em>
I hope it helps!