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OLEGan [10]
3 years ago
6

Given: x - 5 > -2. Choose the solution set. {x | x R, x > -7} {x | x R, x > -3} {x | x R, x > 3} {x | x R, x > 7}

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

{x | x ∈ R, x > 3}

Step-by-step explanation:

We are given the following inequality:

x - 5 > -2

In order to find the solution, we have to isolate the x on one side. This can be done by adding 5 to both sides of the inequality as shown below:

x - 5 + 5 > -2 + 5

x > 3

So the solution of the inequality is set of all numbers where x > 3. This is represented by 3rd option.

So, {x | x ∈ R, x > 3} is the answer.

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Pls help me not fail
nignag [31]

Answer:

D

Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

      = 18² + 12² - ( 2 × 18 × 12 × cos75° )

      = 324 + 144 - 432cos75°

      = 468 - 111.8

      = 356.2 ( take the square root of both sides )

AC = \sqrt{356.2} ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A

\frac{18}{sinA} = \frac{18.9}{sin75} ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = \frac{18sin75}{18.9} , then

∠ A = sin^{-1} ( \frac{18sin75}{18.9} ) ≈ 66.9°

4 0
3 years ago
A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

3 0
3 years ago
Which expression is equivalent to the one below? 6 ÷ 5<br><br>A 6:1/5<br>B 5:1/6<br>C 5/6<br>D 30​
vlada-n [284]

Answer:

option A

Step-by-step explanation:

6:1/5 can also be written as 6/1÷5 which equals to 6÷5

7 0
3 years ago
Read 2 more answers
Q2. Use one of the symbols or = to make this correct: (01)<br><br> 2/5 ______ 2/3
Korolek [52]

Answer:

2/5 is less than 2/3

2/5 < 2/3

Step-by-step explanation:

2/5 x 3=6/15 is small

2/3x5=1<u>0/15 is big</u>

6 0
3 years ago
PLEASE HELP ITS A TIMED QUIZ IM DESPERATE ILL GIVE U BRAINLIEST AND A THANKS PLEASE
den301095 [7]

Answer:

2000 = 600 + 2/5x ; 3500 ft

How To Solve:

2000 = 600 + 2/5x

Combine multiplied terms into a single fraction

2000 = 600 + 2/5x

2000 = 600 + 2x/5

Subtract 600 from both sides of the equation

2000 = 600 + 2x/5

2000 - 600 = 600 + 2x/5 - 600

Simplify

Subtract the numbers

1400 = 600 + 2x/5 − 600

Subtract the numbers

1400 = 2x/5

Solution

X = 3500

7 0
3 years ago
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