You add the two results together and then you divide it by two to get the mid point:
-5,8 + 5,-8 = 0,0
0,0 / 2 = 0,0

The mid point is the centre,
Hope this helps! :)

4 0

3 years ago

Read 2 more answers

Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different

IgorC [24]

Answer:

$20$

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players $=6$

total teams to be formed $=2$

total players in one team $=3$

we have to number of ways of selecting $3$ players for one team, rest $3$ will go in other team.

Total number of ways of selecting $3$ players $=^6C_3$

$=\frac{6!}{3!3!}$

$=20$

Hence total number of different ways in which they can be put into two different teams is $6$

5 0

3 years ago

To find 5, Beau found 22 = 4 and 32 = 9. He said that since 5 is between 4 and 9, 5 is between 2 and 3. Beau thinks a good estim

shusha [124]

Complete question

To find $\sqrt{5}$ , Beau found $2^2 = 4$ and $3^2 = 9$ . He said that since 5 is between 4 and 9, $\sqrt{5}$ , is between 2 and 3. Beau thinks a good estimate for $\sqrt{5}$ , is $\frac{2 + 3}{2} = 2.5$ Is his estimate high or low? How do you know?