Factor 6c^2 +13c +6<br><br>Please help!!!

Can I get the answers for number 14 plz?

nataly862011 [7]

A.
-1:
$2(2)^{-1} \\ 2( \frac{1}{2}) \\ \frac{2}{2} \\ 1$
(-1,1)

0:
$2(2)^{0} \\ 2(1) \\ 2$
(0, 2)

1:
$2(2)^{1} \\ 2(2) \\ 4$
(1, 4)

2:
$2(2)^{2} \\ 2(4) \\ 8$
(2, 8)

3:
$2(2) ^{3} \\ 2(8) \\ 16$
(3,16)

b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.

Hope this helps!

8 0

3 years ago

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a. Determine all bijections from the {1,2,3} into {a,b,c}. b. Determine all bijections from {1, 2, 3} into {a,b,c,d}.

avanturin [10]

Part A

There are 6 bijections from {1,2,3} to {a,b,c}. This is effectively the same as asking the question "how many ways are there to arrange {a,b,c} where order matters?" We use a factorial to answer this question.

3 factorial = 3! = 3*2*1 = 6

You can also use a permutation, which is composed of factorials, to get the same answer.

======================================================

Part B

There are no bijections from {1,2,3} to {a,b,c,d}. Why is this? Because a bijection has two properties: it must be one-to-one, and it must be onto. The term "onto" in mathematics means "every value in the range is targeted". In the case of the range {a,b,c,d} it is not possible for each value to show up. This is because there are only three items in the domain {1,2,3}. You'll always be one letter short.

As you can probably guess, a bijection is only possible if and only if n(D) = n(R), where D and R are the domain and range respectively. The notation n(D) represents the count or number of items in set D.

3 0

3 years ago

Help me Explain Answer for A

Olenka [21]

Each time a rider is added, the cost of lunch goes up $4.25. L=n4.25

5 0

3 years ago

2) Consider the quadratic sequence 72, 100, 120, 132

slava [35]

Answer:

Tn = -4n²+40n+36

Step-by-step explanation:

A general quadratic sequence, Tn = an²+bn+c, where n is the term of the sequence.

So, when n = 1, Tn = 72, which means T1 = a+b+c=72.

when n = 2, Tn = 100, which means T2= 4a+2b+c = 100

when n = 3, Tn = 132, which means T3 = 9a+3b+c = 132.

Now, use a calcaulatot to solve the 3 variable simultaneous equation. According to my calculator, a = -4, b = 40, c = 36.

Hence, you a, b, and c in the Tn equation given above.

Therefore, <em>Tn = -4n²+40n+36</em>

5 0

3 years ago

Please answer please this now in two minutes

Nutka1998 [239]

Answer:

B. 1 and 8

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Factor 6c^2 +13c +6Please help!!!