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Nonamiya [84]
2 years ago
14

What is the equivalent expression to 7/5y.

Mathematics
1 answer:
-BARSIC- [3]2 years ago
4 0

Answer:

7 * 1/5y

Step-by-step explanation:

division is the same as multiplying it by the quantity under 1 so 7 times 1/5y is the equivalent expression

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Why is C the answer for this question?
Grace [21]

Step-by-step explanation:

A left Riemann sum approximates a definite integral as:

\int\limits^b_a {f(x)} \, dx \approx \sum\limits_{k=1}^{n}f(x_{k}) \Delta x \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times (k-1)

Given ∫₂⁸ cos(x²) dx:

a = 2, b = 8, and f(x) = cos(x²)

Therefore, Δx = 6/n and x = 2 + (6/n) (k − 1).

Plugging into the sum:

∑₁ⁿ cos((2 + (6/n) (k − 1))²) (6/n)

Therefore, the answer is C.  Notice that answer D would be a right Riemann sum rather than a left (uses k instead of k−1).

8 0
3 years ago
3cis(5pi/4) in polar form
madreJ [45]
Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)

Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034
8 0
2 years ago
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AlladinOne [14]

Answer:

the domain of the function is 1 >= y >=9

5 0
3 years ago
En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
27 players for 12 spots
labwork [276]

Answer: 27/12=2.25

Pretty simple:)

Step-by-step explanation:

7 0
3 years ago
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