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2 years ago

Yx -³ / 3x⁰ Please help!!

2 answers:

6 0

Hey, i’d love to help you but there seems to be a typo in your equation because a minus sign (or negative sign) can’t be raised to the power of 3.

Marat540 [252]2 years ago

4 0

I'll assume you meant yx^(-3) over 3x^0.

Rewrite this as:

-----------------

x^3*3*x^0

Note that x^3 * x^0 = x^(3+0) = x^3, so that we are left with

------- is the simplest possible answer

x^3

Note that x^0 = 1

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kipiarov [429]

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2 years ago

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1 year ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

2 years ago

I need help with this please I’m dumb

Inessa [10]

Answer:

For number 2 the answer is X=5,-2

and for number 3 the answer is there is no solution

5 0

3 years ago

PLEASE ANSWER ASAP WILL MARK BRAINLIEST SHOW WORK

goldenfox [79]

Answer: y=23

Step-by-step explanation: You find the slope by doing rise over run. You go up 6 units and right two units to get from your first point to your second point. (This means your slope is 6/2 which is 3 btw). So with this problem specifically, you can see that the y values increase by 6 each time so all you do is add 6 again since it is a linear (straight line) function

5 0

3 years ago