Answer:
Find the LCD of the first two, then the LCD of that and the third one.
Step-by-step explanation:
You can do it by finding the LCD of two of the denominators, then the LCD of that and the third denominator.
Or, you can factor each of the denominators and find their LCM by multiplying the unique factors to their highest powers.
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<u>Example:</u>
1/21 + 1/35 + 1/45
The LCD of 1/21 and 1/35 is (21·35)/5 = 105. The LCD of 1/105 and 1/45 is ...
(105·45)/15 = 315
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Using factoring ...
- 21 = 3·7
- 35 = 5·7
- 45 = 3²·5
LCD = 3²·5·7 = 315
Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:
Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Answer: 4(x+3)= 8x-12
Step-by-step explanation:
Answer:
Death Valley California
C(t) = -0.30 (0)² + 40
C(t) = 40
C(t) = -0.30 (12)² + 40t – 12)2 + 40
65f
