Question

Check ALL of the CORRECT answers

Answer 1

Your equation is

$(x-8)^2 = 7$

So, you're asking that the left hand side, squared, must be 7.

There are only two possibilities for a number to give 7 then squared: that number is even the square root of 7 or its opposite.

So, one solution is given by $x-8 = \sqrt{7} \implies x = 8+\sqrt{7}$.

The other is given by $x-8 = -\sqrt{7} \implies x = 8-\sqrt{7}$.