Answer:
The mistake stems from the assumption that angle dab and abc are both 90 and ad = bc and that the perpendicular bisector of dc is different from the perpendicular bisector to ab because they are the same and abcd is a rectangle.
Step-by-step explanation:
If ∡dab = ∡abc and side ab is equal to side bc which are opposite sides, ten then ab is parallel to bc which means the quadrilateral is parallelogram. Also since two angles of the four angles of the parallelogram are 90 degrees then the parallelogram is a rectangle.
The bisector of one side of a rectangle will also bisect the opposite side of the rectangle. Therefore the bisector of dc is the same as the bisector of ab and it meets ab at the midpoint of ab. Therefore p is now at the midpoint of ab and there are no triangles pad and pbc.
To do this problem you must find the GCF or the greatest common factor of 36 and 42. For example 36 can be made by 1 and 36 2 and 18 3 and 12 4 and 9 and 6 and 6. 42 can be made by 1 and 42 2 and 21 3 and 14 and 6 and 7. The highest common factor is 6. So, if you put 6 berries on all of the desserts, you will put 6 strawberries on 6 tarts and 6 blueberries on 7 tarts. That’s a total of 13 desserts
1...2...5...10 are the factors of 20 that go into 50.
About 6.5 I believe, I looked it up and a gross was a total of 144 of something, also known as a dozen dozen.
Given:
A figure of a quadrilateral.
To find:
The measures of angle 1 and angle 2.
Solution:
The given figure has two pairs of congruent adjacent sides. So, the quadrilateral in the figure is a kite.
We know that the diagonals of a kit are perpendicular to each other at the point of intersection.
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.
Therefore, the correct option is C.
