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2 years ago

Evaluate 4 2/3-(-1 4/5)

Mathematics

1 answer:

Blababa [14]2 years ago

3 0

Find a common denominator by multiplying the two different denominators by each other to get 15. 2/3 then becomes 10/15 and 4/5 becomes 12/15.

You now have 4 and 10/15 minus negative 1 and 12/15. Subtracting a negative number results in addition, so it's 4 and 10/15 PLUS 1 and 12/15. You get 5 and 22/15, which becomes 6 and 7/15.

The answer is C.

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How do i cross multiply

atroni [7]

First, ensure that both sides are single fractions:

$\dfrac{a}{b} = \dfrac{c}{d}$

By cross multiply, we mean:

1. multiplying the numerator of the left hand side with the denominator of the right hand side.
2.multiplying the numerator of the right hand side with the denominator of the left hand side.

That is ..
a x d = c x b

6 0

3 years ago

for a science experiment marcia dissolved 1.0 kilograms of salt in 3.0 liters of water for a different experiment Bobby dissolve

Kay [80]

Marcia dissolved 1 kg of salt in 3 litres of water.
Bobby dissolves 2 pounds of salt in 7 pints of water
2.11 pints = 1 litre
7 pints = 7/2.11
= 3.32 litre
1 pound =0.45 kg
2 pound = o.45*2 kg
= 0.9 kg
So we find that Bobby is dissolving 0.9kg of salt in 3.32 litre of water
Marcia is dissolving 1 kg of salt in 3 litres of water.
So it can be said that Marcia made a more concentrated salt solution.

7 0

3 years ago

-4-3 (6x + 9) = 41?<br> Explain what to do first and what is the answer

lara31 [8.8K]

Answer:

x = -2

Step-by-step explanation:

- 3 x - 6x = -18x

- 4 - 18x + 9 = 41

9 - 4 = 5

- 18x + 5 = 41

- 18x = 41 - 5

- 18x = 36

36 divided by -18 is -2

8 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

11 months ago

How do u simplify this: sqrt =square root<br> 2sqrt462cd^2 * sqrt7c^5d^2

Sveta_85 [38]

Answer: The simplified version of this is 14d²c³√66

Step-by-step explanation:

6 0

2 years ago