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Lemur [1.5K]
3 years ago
7

So I have 5 cats and eat 2819 how many do I have left

Mathematics
2 answers:
olga55 [171]3 years ago
7 0

Answer:

-2814

Step-by-step explanation:

5 cats, u eat 2819 of them, that means u have negative 2819

ExtremeBDS [4]3 years ago
7 0
The answer is negative 2814 “-2814” hope this helped!!
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YOU WILL GET BRAINLIST!!!!!!!!<br> Rewrite the following mixed number as a decimal.<br> 17 35/50
sladkih [1.3K]

Answer:

17.7

Step-by-step explanation:

<em>First off, we do not need to do anything to the 17, it is already set up for a decimal. So we have to find out how much 1/50 is so we divide:</em>

<u>Divide:</u>

1/50=0.02

<u>Multiply by 35:</u>

0.02 times 35= 0.7

<u>Add the 17:</u>

17+0.7=<em><u>17.7</u></em>

I hope this helps u pls give a brainliest and a thx ;)

leave a comment if i am wrong

7 0
3 years ago
What is credit
Vladimir79 [104]

I believe the answer would be C; but I'm not sure if this is the right category for this question?

7 0
3 years ago
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What is the mode for 46 47 52 55 64 69 70 78
ziro4ka [17]

Answer:

No mode.

Step-by-step explanation:

No mode.

None of the numbers repeat and since the mode is the most frequent number there isn't one.

8 0
3 years ago
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Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
Five times the difference of twice a number and three, decreased by the sum of the number and eight, equals 13
denis23 [38]
5(2x-3)-(x+8)=13
10x-15-x-8=13
9x-23=13
9x=36
x=4
7 0
3 years ago
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