Answer:
a). Mileage for carA=
, and mileage for carB=
b).total mileage for both is similar to average of them= 
=![\frac{5x+4}{2x(x+1)}[tex]mil/gal](https://tex.z-dn.net/?f=%5Cfrac%7B5x%2B4%7D%7B2x%28x%2B1%29%7D%5Btex%5Dmil%2Fgal)
Step-by-step explanation:
It is given that the distance traveled by car 
And distance traveled by car 
We know the mileage is mile/gallon,
a).So mileage of car

Similarly , the mileage for car


b).total mileage for both is similar to average of them= 

Now divide by 2 for total(average) mileage.
.
Thus those are the answers.
The answer to your question is -10
We have that
<span> |x+6| >= 5
step 1
resolve for (x+6)>=5------> x>=5-6-------> x>= -1
the solution is the interval </span>(-1, ∞)
<span>
step 2
resolve for -(x+6) >=5------> -x-6 >=5----> -x >= 5+6---> -x>=11----> x<=-11
</span>the solution is the interval (-∞, -11)
<span>
using a graph tool
see the attached figure
the solution is the interval (-</span>
∞, -11) ∩ (-1, ∞)
Answer:
- Infinitely many solutions
Step-by-step explanation:
First, let's organize the equations of the lines into slope-intercept form.
- x + 4y = 1
- => 4y = -x + 1
- => y = -x/4 + 1/4
And,
- 2x + 8y = 2
- => 8y = -2x + 2
- => y = -2x/8 + 2/8
- => y = -x/4 + 1/4
Since both the graphs are the same, the two equations have infinitely many solutions.