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Bess [88]
3 years ago
12

A cafe only sells two types of sandwiches, turkey and steak. The cafe charges $4 for turkey sandwiches and $6 for steak sandwich

es. Last month, the cafe sold a total of 925 sandwiches. The cafe sold $4524 worth of sandwiches.
How many TURKEY sandwiches did they sell?

Write a system of equations and SOLVE for turkey!

SHOW your work.

2 points for writing the equations

2 points for showing your work

2 points for figuring out how many turkey sandwiches were sold.
Question 7 options:
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

513 turkey sandwiches were sold.

Step-by-step explanation:

Let's use x to represent turkey sandwiches and y to represent steak sandwiches.

x = turkey sandwiches

y = steak sandwiches

x + y = 925 total sandwiches that were sold

4x + 6y = 4524 dollars that were made

x + y = 925\\y = 925 - x

Now that we know what y (steak sandwiches) equals, we plug it in to an equation to find x.

4x + 6(925-x) = 4524\\4x + 5550 -6x=4524\\

Now, we subtract 5,550 from BOTH sides so we can get x by itself.

-2x + 5550 - 5550 = 4524 - 5550\\-2x = -1026

Next, we divide both sides by 2, so x is bare.

\frac{2x}{2} = \frac{1026}{2}

x = 513

Since x represents turkey sandwiches, we have our answer: 513 turkey sandwiches were sold.

I hope this helps! :)

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Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29

The associated matrix to the system is

\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

3.

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]

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\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]

Using backward substitution we have that

0x_5=-140, then 0=-140 and this is absurd. Then The system is inconsistent.

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