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3 years ago

If the tank is then field to capacity how many half-gallon bottles how many cords will it make?

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

Divide 12 by 4 first to figure out how many gallons are in each 1/4 of the tank.

12/4=3

So if I added another 1/4 to the capacity:

It could hold 15 gallons.

All you have to do to find how many half bottles can be filled is to times 15 by two since we are filling half gallon bottles.

15x2=30

30 bottles.

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One earns $11 per hour and works at most 30 hours per week identify the independent and dependent quantity in the situation and

morpeh [17]

30 hours = 11x30=330$.

8 0

3 years ago

The mean age when smokers first start is 13 years old with a population standard deviation of 2 years. A researcher thinks that

lakkis [162]

Answer:

Null hypothesis: $\mu = 13$

Alternative hypothesis: $\mu \neq 13$

$z=\frac{12.2-13}{\frac{2}{\sqrt{30}}}=-2.191$

a. Reject the null hypothesis

c. There is enough evidence to support the claim

Step-by-step explanation:

Data given and notation

$\bar X=12/2$ represent the sample mean

$s=20000$ represent the standard deviation for the sample

$\sigma =2$ represent the population standard deviation

$n=30$ sample size

$\mu_o =13$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the smoking age has significantly changed since the invention of ENDS—electronic nicotine delivery systems, the system of hypothesis would be:

Null hypothesis: $\mu = 13$

Alternative hypothesis: $\mu \neq 13$

Compute the test statistic

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$z=\frac{12.2-13}{\frac{2}{\sqrt{30}}}=-2.191$

What do you conclude? Using the p-value approach

Since is a two tailed test the p value would be:

$p_v =2*P(Z$