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Pachacha [2.7K]
3 years ago
11

On a coordinate plane, 2 triangles are shown. The first triangle has points M (negative 5, 4), N (negative 2, 3), and L (negativ

e 4, 2). The second triangle has points L prime (negative 4, negative 2), M prime (negative 5, negative 4), and N prime (negative 2, negative 3).
What is the rule for the reflection?

rx-axis(x, y) → (–x, y)
ry-axis(x, y) → (–x, y)
rx-axis(x, y) → (x, –y)
ry-axis(x, y) → (x, –y)
Mathematics
2 answers:
worty [1.4K]3 years ago
7 1

Answer:

The rule of the reflection is rx-axis(x, y) → (x, –y) ⇒ 3rd answer

Step-by-step explanation:

Let us revise the reflection on the axes

If point (x , y) reflected across the x-axis , then its image is (x , -y) , the rule of reflection is rx-axis (x , y) → (x , -y)

If point (x , y) reflected across the y-axis , then its image is (-x , y) , the rule of reflection is ry-axis (x , y) → (-x , y)

In Δ LMN

∵ L = (-4 , 2)

∵ M = (-5 , 4)

∵ N = (-2 , 3)

In ΔL'M'N'

∵ L' = (-4 , -2)

∵ M' = (-5 , -4)

∵ N' = (-2 , -3)

The signs of y-coordinates of the vertices of Δ LMN are changed, that means Δ LMN are reflected across the x-axis

∵ The y-coordinate of L is 2 and the y-coordinate of L' is -2

∵ The y-coordinate of M is 4 and the y-coordinate of M' is -4

∵ The y-coordinate of N is 3 and the y-coordinate of N' is -3

∴ Δ LMN is reflected across the x-axis

∴ The image of point (x , y) is (x , -y)

The rule of the reflection is rx-axis(x, y) → (x, –y)

Veronika [31]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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If we want to prove that two right triangles are congruent by knowing that the corresponding hypotenuses and one leg are congruent, we begin as follows:

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