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alex41 [277]
3 years ago
5

What is the measure WXZ equal to

Mathematics
2 answers:
Rudik [331]3 years ago
6 0
The answer is 64 wxz= 64
Tamiku [17]3 years ago
5 0

Answer:

<h2>m \angle WXZ = 64°</h2>

Step-by-step explanation:

From the question the two angles that's

\angle ZXY and \angle WXZ are complementary since they lie on a right angle

Complementary angles are angles that add up to 90°

Let m \angle WXZ be x

To find m \angle WXZ add up the two angles and equate them to 180° to find the angle

So we have

\angle WXZ + \angle ZXY = 90

x + 26 = 90

x = 90 - 26

x = 64°

So we have the final answer as

<h3>m \angle WXZ = 64°</h3>

Hope this helps you

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There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the
LiRa [457]

Answer:

No. of juniors = 14

No. of seniors = 16

Total students = 30

A) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

Since we are asked about arrangement so we will use permutation

Formula : ^nP_r=\frac{n!}{(n-r)!}

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^{30}P_5=\frac{30!}{(30-5)!}

^{30}P_5=17100720

So, From the 30 members, there are 17100720 ways to arrange 5 members of the club in a line?

B) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

Out of 16 seniors 2 will be selected

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Remaining students = 30-2 = 28

So, out of 28 students 3 students will be selected

No. of ways = ^{16}P_2 \times ^{28}P_3

No. of ways = \frac{16!}{(16-2)!}\times\frac{28!}{(28-3)!}

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C)If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Since we are not asked about arrangement so we will use combination

Out of 16 seniors 2 will be selected

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Formula : ^nC_r=\frac{n!}{r!(n-r)!}

So, No. of possible groupings = ^{16}C_2 \times ^{14}C_2

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If the club sends 2 juniors and 2 seniors to the tournament, there are 10920 possible groupings

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Out of 16 seniors 4 will be selected

or

Out of 14 juniors 4 will be selected

So, No. of possible groupings = ^{16}C_4 + ^{14}C_4

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                                                  = 2821

So,If the club sends either 4 juniors or 4 seniors, there are 2821 possible groupings .

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Step-by-step explanation:

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Answer:

See below

Step-by-step explanation:

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Hello!

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Step-by-step explanation:

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