Hey dhsidvxhejfbeifbshdjdbd
Answer:
A) A(t) = 4500*π - 1600*t
B) A(4) = 7730 in³
C) t = 8,8 sec
Step-by-step explanation:
The volume of the sphere is:
d max = 30 r max = 15 in
V(s) = (4/3)*π*r³ V(s) = (4/3)*π* (15)³
V(s) = 4500*π
A) Amount of air needed to fill the ball A(t)
A(t) = Total max. volume of the sphere - rate of flux of air * time
A(t) = 4500*π - 1600*t in³
B) After 4 minutes
A(4) = 4500*π - 6400
A(4) = 14130 - 6400
A(4) = 7730 in³
C) A(t) = 4500*π - 1600*t
when A(t) = 0 the ball got its maximum volume then:
4500*π - 1600*t = 0
t = 14130/1600
t = 8,8 sec
You would have to add a positive 6 to the negative 6 to get zero. Lets say you have -2 in order to get it to zero or just any positive number, you have to add a positive of the same value or higher to be able to get it there. I hope you understand that.
Answer:
f(x) = 54(two-thirds) Superscript x minus 1
Step-by-step explanation:
Given that:
First peak : 36 / 54=2/3
Second peak : 24 / 36 = 2/3
The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height
Modeling this using geometric progression :
An=a1r^(n-1)
An = nth term of a geometric progression
a1=first term
r=common ratio = 2/3
n = nth term
a1=54
Substituting into the above formular :
An=54(2/3)^(n-1)
I pretty sure you would use x over 38.00 = 20 over 100 then cross multiply them
