The summand (R?) is missing, but we can always come up with another one.
Divide the interval [0, 1] into
subintervals of equal length
:
![[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%3D%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%5Ccup%5Ccdots%5Ccup%5Cleft%5B1-%5Cdfrac1n%2C1%5Cright%5D)
Let's consider a left-endpoint sum, so that we take values of
where
is given by the sequence

with
. Then the definite integral is equal to the Riemann sum




Answer:
-31
Step-by-step explanation:
We write the equation out

Distribute the -1

Subtract the 19 on both sides

Since the scale factor is greater than 1, this dilation will be an enlargement. Therefore, you multiply 7.2 times 8.1 to get 58.32. This question asks for diameter, so multiply 58.32 times 2 to get 116.64 in.
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%66.666
Because 4/6 times it will be that which is %66.666